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Implement upper and lower current limits in op-amp model (Read 187 times)
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Implement upper and lower current limits in op-amp model
Sep 11th, 2018, 7:26pm
I am trying to model a more accurate op-amp with a current limiting function (different sinking and sourcing currents) and some intuitive parameters for tuning the op-amp characteristics. So I used a transfer function, H(s), to model the ideal op-amp. And then tried to add the current limiting function which is in vain. Could someone give some suggestions? Thanks in advance.

p.s. I am aware of the convergence issue about the numerical difficulties. However, I cannot say I am 100% understand the issue. And I found it some what confusing and causing some difficulties to make two limitations.

Here's my code... I marked out some lines I tried before. So you might have to tweak the code a little bit.
`include "disciplines.vams"
`include "constants.vams"

`define dB2dec(x) pow(10,x/20)

module opamp(vinp,vinm,vdd,vss,voutp);
 inout vinp,vinm,vdd,vss;
 inout voutp;
 electrical vinp,vinm,vdd,vss,voutp;
 electrical n1,n2;

 parameter real gain = 90 from (0:inf),          // open loop gain in dB
            three_dB_freq  = 100 from (0:inf),   // 3dB frequency
            rin  = 10M from (0:inf),             // input resistance
            cin  = 1p from [0:inf),             // input capacitance
            ioutp_max = 20u from (0:inf),        // max. classAB PMOS output current
            ioutn_max = 10u from (0:inf),        // max. classAB NMOS output current
            rout = 1k from (0:inf),              // output resistance
            cout = 1p from (0:inf),              // output capacitance
            vout_offset = 0,
            volc = 1;

 real vin,vout,vout0;
 real voutmax,voutmin;
 real iout;
 real qin = 0;
 real qout = 0;
 real cond1, cond2;

 analog begin

    vin = V(vinp,vinm);
    vout = V(voutp,vss);
    voutmax = V(vdd);
    voutmin = V(vss);

    qin = cin * vin;
    I(vinp,vinm) <+ vin / rin + ddt(qin);

    vout0 = laplace_nd(vin*`dB2dec(gain),{1,0},{1,1/(`M_TWO_PI*three_dB_freq)}) + vout_offset;

    iout = (vout0 - vout) / rout;
/* try
    //cond1 = (vout0-voutmax)/voutmax - (iout-ioutp_max)/ioutp_max;
    //cond2 = (vout0-voutmin) - (iout-(-ioutn_max));
    //if(cond1*cond2<0) begin
    //    if(cond1>0)
    //        vout0 = voutmax;
    //    else
    //        vout0 = voutmin;
    //else begin
    //    if(cond1<0)
    //        iout = ioutp_max;
    //    else if (cond2>0)
    //        iout = -ioutn_max;
end of try*/

/* another try
    // output current limitation
    //case (1)
    //  iout >  ioutp_max : iout =  ioutp_max;
    //  iout < -ioutn_max : iout = -ioutn_max;

    // output voltage limitation
    //if (vout >= vout_offset)
    //    iout = iout*tanh(volc*(voutmax-vout));
    //    iout = iout*tanh(volc*abs(voutmin-vout));
    //iout = slew(iout,ioutp_max*three_dB_freq,-ioutn_max*three_dB_freq);
    //I(voutp,vss) <+ -iout;
end of another try*/

// Here just some codes to let this can be run like an ideal model.
    I(n1,n2) <+ iout;
    V(n2,vss) <+ idt(iout) / cout;
    V(voutp,vss) <+ V(n2,vss);



Here's a testbench. (using HSPICE)

.options post=1
$.options method = gear2only

.param VH = 5
.param VL = 1

Vin in 0 pwl(5u VL 5.1u VH 25u VH 25.1u VL)

Vdd Vdd 0 6
Vss Vss 0 0

Vfb Vfb VOUT DC=0

Xopamp1 in Vfb Vdd Vss VOUT opamp

.param RP=3k
.param CP=30p

R1 VOUT V1 'RP/3'
R2 V1   V2 'RP/3'
R3 V2   V3 'RP/3'

C1 V1 0 'CP/3'
C2 V2 0 'CP/3'
C3 V3 0 'CP/3'

.tran 1n 30u
.probe tran v(*) i(*)

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