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a simple inverter verilogA module in Hspice simulation (Read 730 times)

xiaota

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a simple inverter verilogA module in Hspice simulation
Oct 27^th, 2013, 7:24pm

module V_not(in,out);
input in;
output out;
electrical in,out;

parameter real vout_high = 5,
vout_low = 0 from (-inf:vout_high),
vth = 1.4,
tdelay = 5n from [0:inf),
trise = 1n from [0:inf),
tfall = 1n from [0:inf);

analog
begin
@(cross(V(in) - vth, +1));
V(out) <+ transition(vout_high,tdelay,trise,tfall);
@(cross(V(in) - vth, -1));
V(out) <+ transition(vout_low,tdelay,trise,tfall);
end
endmodule

any question with the above inv module
when I use it in Hspice ,I can not get the right result

.hdl '.\not.va'
Xinv A Y V_not

*Vin A 0 pat(5 0 0 100n 100n 100m b1010 rb=0 r=-1)
Vin A 0 pwl(0 0 250m 5 500m 0)
.tran 1m 500m

.end

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Geoffrey_Coram

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Posts: 1998
Massachusetts, USA

Re: a simple inverter verilogA module in Hspice simulation
Reply #1 - Nov 5^th, 2013, 8:25am

The simulator should not allow you to put a contribution V(out) <+ inside a cross event. �And actually, now that I look at your code, you aren't; what you really have is

Code:

 � �@(cross(V(in) - vth, +1))
 � � � �;
 � �V(out) <+ transition(vout_high,tdelay,trise,tfall);
 � �@(cross(V(in) - vth, -1))
 � � � �;
 � �V(out) <+ transition(vout_low,tdelay,trise,tfall);

So, the cross events only control the timesteps, and the contributions are always made, and I expect you end up with
� �V(out) <+ vout_high + vout_low;

You need a variable:

Code:

real vout;

analog begin
 � �@(initial_step)
 � � � �vout = 0;

 � �@(cross(V(in) - vth, +1))
 � � � �vout = vout_high;
 � �@(cross(V(in) - vth, -1))
 � � � �vout = vout_low;
 � �V(out) <+ transition(vout,tdelay,trise,tfall);
 �end
endmodule

If at first you do succeed, STOP, raise your standards, and stop wasting your time.

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